Nyatakan bilangan-bilangan
decimal berkut dalam system bilangan :
a.
Biner
b.
Octal
c.
Hexadecimal
Penyelesaian :
a. Biner
·
21
21 : 2 = 10 sisa 1
10 : 2 = 5 sisa 0
5 : 2 = 2 sisa 1
2 : 2 = 1 sisa 0
1 : 2 = 0 sisa 1
ð 21 =
10101
·
137
137 : 2 = 68 sisa
1
68 : 2 = 34 sisa 0
34 : 2 = 17 sisa 0
17 2 = 8 sisa 1
8
: 2 = 4 sisa 0
4 : 2 = 2 sisa 0
2 : 2 = 1 sisa 0
1 : 2 = 0 sisa 1
ð 137 = 10001001
·
320
320 : 2 = 160 sisa
0
160 : 2 = 80 sisa 0
80 : 2 = 40 sisa 0
40 : 2 =
20 sisa 0
20 : 2 =
10 sisa 0
10 : 2 =
5 sisa 0
5 : 2 =
2 sisa 1
2 : 2 =
1 sisa 0
1 : 2 =
0 sisa 1
ð 320 = 101000000
·
161
161 : 2 = 80 sisa
1
80 : 2 = 40 sisa 0
40 : 2 = 20 sisa 0
20 : 2 = 10 sisa 0
10 : 2 = 5 sisa 0
5 : 2 = 2 sisa 1
2
: 2 = 1 sisa 0
1 : 2 = 0 sisa 1
ð 161 = 10100001
·
2400
2400 : 2 = 1200
sisa 0
1200 : 2 = 600 sisa 0
600 : 2 =
300 sisa 0
300 : 2 =
150 sisa 0
150 : 2 =
75 sisa 0
75 : 2 =
37 sisa 1
37 : 2 =
18 sisa 1
18 : 2 = 9 sisa 0
9 : 2 = 4 sisa 1
4 : 2 = 2 sisa 0
2 : 2 = 1 sisa 0
1 : 2 = 0 sisa 1
ð 2400 = 100101100000
·
9101
9101 : 2 = 4550
sisa 1
4550 : 2 = 2275
sisa 0
2275 : 2 = 1137
sisa 1
1137 : 2 = 568 sisa 1
568 : 2 =
284 sisa 0
284 : 2 =
142 sisa 0
142 : 2 =
71 sisa 0
71 : 2 = 35 sisa 1
35 : 2 = 17 sisa 1
17 : 2 = 8 sisa 1
8 : 2 = 4 sisa 0
4 : 2 = 2 sisa 0
2 : 2 = 1 sisa 0
1 : 2 = 0 sisa 1
ð 9101 = 10001110001101
b.Octal
·
21
21 : 8 = 2 sisa 5
2: 8 =0
sisa 2
Jadi,
21 = 25
·
137
137 : 8 = 17 sisa 1
17 : 8 = 2 sisa 1
2 : 8 = 0 sisa 2
Jadi,
137 = 211
·
320
320 : 8 = 40 sisa 0
40 : 8 = 5 sisa 0
5 : 8 = 0 sisa 5
Jadi, 320 = 500
·
161
161 : 8 = 20
sisa 1
20 : 8 = 2 sisa 4
2 : 8 = 0 sisa 2
Jadi, 161 = 241
·
2400
2400 : 8 = 300 sisa 0
300 : 8 = 37 sisa 4
37 : 8 = 4 sisa 5
4 : 8 = 0 sisa 4
Jadi,
2400 = 4540
·
9101
9101 : 8 = 1137 sisa 5
1137 : 8 = 142 sisa 1
142 : 8 = 17 sisa 6
17 : 8 =2 sisa 1
2 : 8 = 0 sisa 2
Jadi, 9101 = 21615
c. Hexadesimal
·
21
21: 16 = 1 sisa 5
1 : 16 = 0 sisa 1
Jadi, 21 = 15
·
137
137
: 16 = 8 sisa 9
8 : 16 = 0 sisa 8
Jadi, 137 = 89
·
320
320
: 16 = 20 sisa 0
20 : 16 = 1 sisa 4
1 : 16 = 0 sisa 1
Jadi, 320 = 140
·
161
161 : 16 = 10 sisa 1
10 : 16 = 0 sisa 10 (A)
Jadi, 161 = A1
·
2400
2400
: 16 = 150 sisa 0
150 : 16 = 9 sisa 6
9
: 16 = 0 sisa 9
Jadi, 2400 = 960
·
9101
9101
: 16 = 568 sisa 13 (D)
568 : 16 = 35 sisa 8
35 : 16 = 2 sisa 3
2 : 16 = 0 sisa 2
Jadi, 9101 = 238D
“Fakultas-TIKOM” dalam bilangan biner :
·
F = 6
128 64 32 16 8 4 2 1
0
1 0 0 0 1 1 0
F = 01000110
·
a = 1
128 64 32 16 8 4 2 1
0
1 1 0 0 0 0 1
a = 01100001
·
k = 11
128 64 32 16 8 4 2 1
0
1 1 0 1 0 1 1
k = 01101011
·
u = 21
128 64 32 16 8 4 2 1
0
1 1 1 0 1 0 1
u = 01110101
·
l = 12
128 64 32 16 8 4 2 1
0
1 1 0 1 1 0 0
l = 01101100
·
t = 20
128 64 32 16 8 4 2 1
0
1 1 1 0 1 0 0
t = 01110100
·
a = 1
128 64 32 16 8 4 2 1
0
1 1 0 0 0 0 1
a = 01100001
·
s = 19
128 64 32 16 8 4 2 1
0
1 1 1 0 0 1 1
s = 01110011
·
- = 2D
(2
×16¹)+(13×16°)
32
+ 13 = 47
128 64 32 16 8 4 2 1
0 0 1
0 1 1 1 1
= 00101111
·
T = 20
128 64 32 16 8 4 2 1
0
1 0 1 0 1 0 0
T = 01010100
·
I = 9
128 64 32 16 8 4 2 1
0
1 0 0 1 0 0 1
I = 01001001
·
K = 11
128 64 32 16 8 4 2 1
0
1 0 0 1 0 1 1
K = 01001011
·
O = 15
128 64 32 16 8 4 2 1
0
1 0 0 1 1 1 1
O = 01001111
·
M = 13
128 64 32 16 8 4 2 1
0
1 0 0 1 1 0 1
M = 01001101
01000110 01100001 01101011 01110101 01101100 01110100 01100001 01110011 00101111
01010100 01001001 01001011 01001111 01001101
Sebuah harddisk 2 Tb berisikan
file-file sebagai berikut :
a. File Video 3.210.987, dengan per
file 160 Mb dengan durasi 60 menit dengan penjelasan setengah dari file
tersebut durasi 30 menit dan setengahnya 49 menit.
b. File Save Game 9.456, dengan per
file 190 Kb
c. File Gambar 19.190, dengan per file
19.191.199 bit
Jika harddisk tersebut telah berisikan
sistem 190.199.199 bit, berapakah sisa kapasitas dari harddisk tersebut?
Jawaban
Diketahui :
1 byte = 8 bit
1 kilobyte = 1024 byte
1 megabyte = 1024 kilobyte
1 gigabyte = 1024 megabyte
1 terabyte = 1024 gigabyte
• Harddisk
2 Tb = 2048 Gb = 2097152 Mb = 2147483648 Kb = 2199023255552 byte =
17592186044416 bit
• Sistem
= 190.199.199 bit
a. 160 Mb = 163840 Kb = 167772160 byte
= 171798691840 bit
File Video 3.210.987 X 171798691840
bit = 551643366115246080 bit
b. 190 Kb = 194560 byte = 199229440
bit
File Save Game 9.456 X 199229440 bit =
1883913584640 bit
c. File Gambar 19.190 X 19.191.199 bit
= 368279108810 bit
Penyelesaian:
17592186044416
bit – (551643366115246080 bit + 1883913584640 bit + 368279108810 bit + 190.199.199
bit) = -551628026312094313 bit
